top 5 on the list

PanagiotisCharalampous
22 Oct 2018, 10:38

Hi Sasha,

You can use the following tools

1. Dictionary. Add your entries as values and your index as keys.

2, Sort function. Sort your dictionary using the keys.

3. Take function. Take the top x entries of the sorted dictionary.

Let me know if the above helps.

Best Regards,

Panagiotis

alexander.n.fedorov
22 Oct 2018, 10:41

I do not want it sorted, then I loose important information

Maybe I can circle them or use LINWQ?
I just do not know how

But I do not want to change the original structure of the list

PanagiotisCharalampous
22 Oct 2018, 11:19

Hi Sasha,

OrderBy will not sort the original list/dictionary. It will return a new sorted instance.

Best Regards,

Panagiotis

alexander.n.fedorov
22 Oct 2018, 14:22

RE:

Panagiotis Charalampous said:

Hi Sasha,

OrderBy will not sort the original list/dictionary. It will return a new sorted instance.

Best Regards,

Panagiotis

Unfortunately, I do not know how to do that, so  I guess I will have to find a book and study

PanagiotisCharalampous
22 Oct 2018, 14:33

Here is an example

            var dictionary = new Dictionary<int, int>();
            dictionary.Add(1, 3);
            dictionary.Add(2, 5);
            dictionary.Add(3, 1);
            dictionary.Add(4, 2);
            dictionary.Add(5, 9);
            dictionary.Add(6, 4);
            dictionary.Add(7, 7);
            dictionary.Add(8, 6);
            dictionary.Add(9, 10);
            dictionary.Add(10, 8);

            foreach (var v in dictionary.OrderBy(x => x.Value).Take(5))
            {
                Print("Index: " + v.Key + " Value: " + v.Value);
            }

Best Regards,

Panagiotis

alexander.n.fedorov
22 Oct 2018, 14:43

RE:

Panagiotis Charalampous said:

Here is an example

            var dictionary = new Dictionary<int, int>();
            dictionary.Add(1, 3);
            dictionary.Add(2, 5);
            dictionary.Add(3, 1);
            dictionary.Add(4, 2);
            dictionary.Add(5, 9);
            dictionary.Add(6, 4);
            dictionary.Add(7, 7);
            dictionary.Add(8, 6);
            dictionary.Add(9, 10);
            dictionary.Add(10, 8);

            foreach (var v in dictionary.OrderBy(x => x.Value).Take(5))
            {
                Print("Index: " + v.Key + " Value: " + v.Value);
            }

Best Regards,

Panagiotis

Thank you Panagiotis, I will try to think of it

Regards

 

alexander.n.fedorov
22 Oct 2018, 15:09

So, Dictionary is like 2 dimensional (kind of) list and you would do

"

for (int i=0.........)

{

     dictionary.Add(i+1, numbers[i]

}

?

alexander.n.fedorov
22 Oct 2018, 15:09

for (int i=0.........)

{

     dictionary.Add(i+1, numbers[i])

}

?

alexander.n.fedorov
22 Oct 2018, 16:27

RE:

alexander.n.fedorov said:

So, Dictionary is like 2 dimensional (kind of) list and you would do

 

"

for (int i=0.........)

{

     dictionary.Add(i+1, numbers[i]

}

?

Thanks, Panagiotis, it helped a lot!